2x+35=x^2+4x

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Solution for 2x+35=x^2+4x equation:


Simplifying
2x + 35 = x2 + 4x

Reorder the terms:
35 + 2x = x2 + 4x

Reorder the terms:
35 + 2x = 4x + x2

Solving
35 + 2x = 4x + x2

Solving for variable 'x'.

Combine like terms: 2x + -4x = -2x
35 + -2x + -1x2 = 4x + x2 + -4x + -1x2

Reorder the terms:
35 + -2x + -1x2 = 4x + -4x + x2 + -1x2

Combine like terms: 4x + -4x = 0
35 + -2x + -1x2 = 0 + x2 + -1x2
35 + -2x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
35 + -2x + -1x2 = 0

Factor a trinomial.
(5 + -1x)(7 + x) = 0

Subproblem 1

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Subproblem 2

Set the factor '(7 + x)' equal to zero and attempt to solve: Simplifying 7 + x = 0 Solving 7 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 0 + -7 Combine like terms: 7 + -7 = 0 0 + x = 0 + -7 x = 0 + -7 Combine like terms: 0 + -7 = -7 x = -7 Simplifying x = -7

Solution

x = {5, -7}

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